q=%28%E8%8B%B1%29J.+K.%E7%BD%97%E7%90%B3%28J.+K.+Rowling%29&searchType=standard&isFacet=true&view=standard&booktype=1&booktype=2&rows=10&sortWay=score&sortOrder=desc&curlibcode=JNST&searchWay0=marc&logical0=AND
booktype=1&booktype=2&rows=10&curlibcode=JNST&searchWay0=marc&logical0=AND
(英)J. K.罗琳(J. K. Rowling)